Method One:
1. Determine the balanced chemical equation for the chemical reaction.
2. Convert all given information into moles.
3. Calculate the mole ratio from the given information. Compare the calculated ratio to the actual ratio.
4. Use the amount of limiting reagent to calculate the amount of product produced.
5. If necessary, calculate how much is left in excess of the non-limiting reagent.
Method Two:
1. Balance the chemical equation for the chemical reaction.
2. Convert the given information into moles.
3. Use stoichiometry for each individual reactant to find the mass of product produced.
4. The reactant that produces a lesser amount of product is the limiting reagent.
5. The reactant that produces a larger amount of product is the excess reagent.
6. To find the amount of remaining excess reactant, subtract the mass of excess reagent consumed from the total mass of excess reagent given.
Here is a website that I found that uses the above methods to work through several examples: Finding Limiting Reagent
Here is another website that has practice problems dealing with this topic: Limiting Reagent Practice Problems
Carly, I found your post very helpful. I like how you described both ways to determine the limiting reagent, showing the viewers that there are options in case they get stuck using on. Also, I found the explanations on your first link very educational, reinforcing what we learned in class. Plus, the practice problems on your second link will come in handy when studying for the final.
ReplyDeleteCarly, I found this post very helpful since we just started learning about this topic. I like how you organized your post into the two distinct ways to find the limiting reagent. Personally, I prefer the second method, but it is great that you showed the other method for people that may not be like me. I also enjoyed your links, as they were very helpful for me when I was studying for tested questions on this topic.
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